In how many different ways can four keys, no two of which are the same, be arranged on a key-ring that has no clasp?

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In how many different ways can four keys, no two of which are the same, be arranged on a key-ring that has no clasp? ​

Answer:

Keep one key fixed in any position in the ring. So, the remaining 4 keys can be arranged in 4! = 24 ways

Step-by-step explanation:

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