A. Solve the combination problem below. 2. In how many ways can a basketball tournament consisting of 12 players be eliminated from 4 elimination round?

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A. Solve the combination problem below. 2. In how many ways can a basketball tournament consisting of 12 players be eliminated from 4 elimination round?​

Answer:

There will be 10C2 pairs to play elimination games.

So there will be. 10!/(8!*2!)=10*9/(1*2)=90/2=45 elimination games.

Step-by-step explanation:

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